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4/5x-1/3x=15
We move all terms to the left:
4/5x-1/3x-(15)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 3x!=0We calculate fractions
x!=0/3
x!=0
x∈R
12x/15x^2+(-5x)/15x^2-15=0
We multiply all the terms by the denominator
12x+(-5x)-15*15x^2=0
Wy multiply elements
-225x^2+12x+(-5x)=0
We get rid of parentheses
-225x^2+12x-5x=0
We add all the numbers together, and all the variables
-225x^2+7x=0
a = -225; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·(-225)·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*-225}=\frac{-14}{-450} =7/225 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*-225}=\frac{0}{-450} =0 $
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