4/5x-(-2/5x)-(+0.6x)=0

Solution for 4/5x-(-2/5x)-(+0.6x)=0 equation:

4/5x-(-2/5x)-(+0.6x)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



Domain of the equation: 5x)!=0

x!=0/1

x!=0

x∈R


We get rid of parentheses

4/5x+2/5x-0.6x=0

We multiply all the terms by the denominator


-(0.6x)*5x+4+2=0

We add all the numbers together, and all the variables

-(+0.6x)*5x+4+2=0

We add all the numbers together, and all the variables

-(+0.6x)*5x+6=0

We multiply parentheses

-0x^2+6=0

We add all the numbers together, and all the variables

-1x^2+6=0

a = -1; b = 0; c = +6;
Δ = b2-4ac
Δ = 02-4·(-1)·6
Δ = 24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{24}=\sqrt{4*6}=\sqrt{4}*\sqrt{6}=2\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{6}}{2*-1}=\frac{0-2\sqrt{6}}{-2}
=-\frac{2\sqrt{6}}{-2}
=-\frac{\sqrt{6}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{6}}{2*-1}=\frac{0+2\sqrt{6}}{-2}
=\frac{2\sqrt{6}}{-2}
=\frac{\sqrt{6}}{-1}
$