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4/5x+8=29+1.5x
We move all terms to the left:
4/5x+8-(29+1.5x)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
4/5x-(1.5x+29)+8=0
We get rid of parentheses
4/5x-1.5x-29+8=0
We multiply all the terms by the denominator
-(1.5x)*5x-29*5x+8*5x+4=0
We add all the numbers together, and all the variables
-(+1.5x)*5x-29*5x+8*5x+4=0
We multiply parentheses
-5x^2-29*5x+8*5x+4=0
Wy multiply elements
-5x^2-145x+40x+4=0
We add all the numbers together, and all the variables
-5x^2-105x+4=0
a = -5; b = -105; c = +4;
Δ = b2-4ac
Δ = -1052-4·(-5)·4
Δ = 11105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-105)-\sqrt{11105}}{2*-5}=\frac{105-\sqrt{11105}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-105)+\sqrt{11105}}{2*-5}=\frac{105+\sqrt{11105}}{-10} $
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