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4/5x+4/5x=10
We move all terms to the left:
4/5x+4/5x-(10)=0
Domain of the equation: 5x!=0We multiply all the terms by the denominator
x!=0/5
x!=0
x∈R
-10*5x+4+4=0
We add all the numbers together, and all the variables
-10*5x+8=0
Wy multiply elements
-50x+8=0
We move all terms containing x to the left, all other terms to the right
-50x=-8
x=-8/-50
x=4/25
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