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4/5x+3/2x=6
We move all terms to the left:
4/5x+3/2x-(6)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 2x!=0We calculate fractions
x!=0/2
x!=0
x∈R
8x/10x^2+15x/10x^2-6=0
We multiply all the terms by the denominator
8x+15x-6*10x^2=0
We add all the numbers together, and all the variables
23x-6*10x^2=0
Wy multiply elements
-60x^2+23x=0
a = -60; b = 23; c = 0;
Δ = b2-4ac
Δ = 232-4·(-60)·0
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-23}{2*-60}=\frac{-46}{-120} =23/60 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+23}{2*-60}=\frac{0}{-120} =0 $
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