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4/5x+2=2x-4
We move all terms to the left:
4/5x+2-(2x-4)=0
Domain of the equation: 5x!=0We get rid of parentheses
x!=0/5
x!=0
x∈R
4/5x-2x+4+2=0
We multiply all the terms by the denominator
-2x*5x+4*5x+2*5x+4=0
Wy multiply elements
-10x^2+20x+10x+4=0
We add all the numbers together, and all the variables
-10x^2+30x+4=0
a = -10; b = 30; c = +4;
Δ = b2-4ac
Δ = 302-4·(-10)·4
Δ = 1060
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1060}=\sqrt{4*265}=\sqrt{4}*\sqrt{265}=2\sqrt{265}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-2\sqrt{265}}{2*-10}=\frac{-30-2\sqrt{265}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+2\sqrt{265}}{2*-10}=\frac{-30+2\sqrt{265}}{-20} $
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