4/5x+17/35=2/7x

Solution for 4/5x+17/35=2/7x equation:

4/5x+17/35=2/7x

We move all terms to the left:

4/5x+17/35-(2/7x)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



Domain of the equation: 7x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

4/5x-(+2/7x)+17/35=0

We get rid of parentheses

4/5x-2/7x+17/35=0

We calculate fractions


4165x^2/3675x^2+2940x/3675x^2+(-1050x)/3675x^2=0

We multiply all the terms by the denominator


4165x^2+2940x+(-1050x)=0

We get rid of parentheses

4165x^2+2940x-1050x=0

We add all the numbers together, and all the variables

4165x^2+1890x=0

a = 4165; b = 1890; c = 0;
Δ = b2-4ac
Δ = 18902-4·4165·0
Δ = 3572100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3572100}=1890$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1890)-1890}{2*4165}=\frac{-3780}{8330}
=-54/119
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1890)+1890}{2*4165}=\frac{0}{8330}
=0
$