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4/5p+2/5(40-p)=0
Domain of the equation: 5p!=0
p!=0/5
p!=0
p∈R
Domain of the equation: 5(40-p)!=0We add all the numbers together, and all the variables
p∈R
4/5p+2/5(-1p+40)=0
We calculate fractions
(20p(-)/(25p^2(-)+10p/(25p^2(-)=0
We calculate terms in parentheses: +(20p(-)/(25p^2(-)+10p/(25p^2(-), so:
20p(-)/(25p^2(-)+10p/(25p^2(-
We can not solve this equation
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