4/5f+1=25

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Solution for 4/5f+1=25 equation: 



4/5f+1=25

We move all terms to the left:

4/5f+1-(25)=0



Domain of the equation: 5f!=0

f!=0/5

f!=0

f∈R



We add all the numbers together, and all the variables

4/5f-24=0

We multiply all the terms by the denominator


-24*5f+4=0

Wy multiply elements

-120f+4=0

We move all terms containing f to the left, all other terms to the right

-120f=-4

f=-4/-120

f=1/30

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