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4/5c+2=2/5
We move all terms to the left:
4/5c+2-(2/5)=0
Domain of the equation: 5c!=0We add all the numbers together, and all the variables
c!=0/5
c!=0
c∈R
4/5c+2-(+2/5)=0
We get rid of parentheses
4/5c+2-2/5=0
We calculate fractions
2!=0
There is no solution for this equation
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