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4/5(x-8)=1/2(x-5)
We move all terms to the left:
4/5(x-8)-(1/2(x-5))=0
Domain of the equation: 5(x-8)!=0
x∈R
Domain of the equation: 2(x-5))!=0We calculate fractions
x∈R
(8xx/(5(x-8)*2(x-5)))+(-5xx/(5(x-8)*2(x-5)))=0
We calculate terms in parentheses: +(8xx/(5(x-8)*2(x-5))), so:
8xx/(5(x-8)*2(x-5))
We multiply all the terms by the denominator
8xx
Back to the equation:
+(8xx)
We calculate terms in parentheses: +(-5xx/(5(x-8)*2(x-5))), so:We get rid of parentheses
-5xx/(5(x-8)*2(x-5))
We multiply all the terms by the denominator
-5xx
Back to the equation:
+(-5xx)
8xx-5xx=0
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