4/5(x+9)=-3/10(2x-5)

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Solution for 4/5(x+9)=-3/10(2x-5) equation: 



4/5(x+9)=-3/10(2x-5)

We move all terms to the left:

4/5(x+9)-(-3/10(2x-5))=0



Domain of the equation: 5(x+9)!=0

x∈R





Domain of the equation: 10(2x-5))!=0

x∈R



We calculate fractions


(40x2/(5(x+9)*10(2x-5)))+(-(-15xx)/(5(x+9)*10(2x-5)))=0



We calculate terms in parentheses: +(40x2/(5(x+9)*10(2x-5))), so:

40x2/(5(x+9)*10(2x-5))

We multiply all the terms by the denominator


40x2

We add all the numbers together, and all the variables

40x^2

Back to the equation:

+(40x^2)





We calculate terms in parentheses: +(-(-15xx)/(5(x+9)*10(2x-5))), so:

-(-15xx)/(5(x+9)*10(2x-5))

We multiply all the terms by the denominator


-(-15xx)

We get rid of parentheses

15xx

Back to the equation:

+(15xx)

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