4/5(35x+30)-20=-2/3(24x-27)

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Solution for 4/5(35x+30)-20=-2/3(24x-27) equation: 



4/5(35x+30)-20=-2/3(24x-27)

We move all terms to the left:

4/5(35x+30)-20-(-2/3(24x-27))=0



Domain of the equation: 5(35x+30)!=0

x∈R





Domain of the equation: 3(24x-27))!=0

x∈R



We calculate fractions


(12x2/(5(35x+30)*3(24x-27)))+(-(-10x3)/(5(35x+30)*3(24x-27)))-20=0



We calculate terms in parentheses: +(12x2/(5(35x+30)*3(24x-27))), so:

12x2/(5(35x+30)*3(24x-27))

We multiply all the terms by the denominator


12x2

We add all the numbers together, and all the variables

12x^2

Back to the equation:

+(12x^2)





We calculate terms in parentheses: +(-(-10x3)/(5(35x+30)*3(24x-27))), so:

-(-10x3)/(5(35x+30)*3(24x-27))

We add all the numbers together, and all the variables

-(-10x^3)/(5(35x+30)*3(24x-27))

We multiply all the terms by the denominator


-(-10x^3)

We do not support expression: x^3

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