4/5(15x+20)-7x=5/6(12x-24)

Solution for 4/5(15x+20)-7x=5/6(12x-24) equation:

4/5(15x+20)-7x=5/6(12x-24)

We move all terms to the left:

4/5(15x+20)-7x-(5/6(12x-24))=0


Domain of the equation: 5(15x+20)!=0

x∈R



Domain of the equation: 6(12x-24))!=0

x∈R


We add all the numbers together, and all the variables

-7x+4/5(15x+20)-(5/6(12x-24))=0

We calculate fractions


-7x+(24x1/(5(15x+20)*6(12x-24)))+(-25x1/(5(15x+20)*6(12x-24)))=0


We calculate terms in parentheses: +(24x1/(5(15x+20)*6(12x-24))), so:

24x1/(5(15x+20)*6(12x-24))

We multiply all the terms by the denominator


24x1

We add all the numbers together, and all the variables

24x

Back to the equation:

+(24x)



We calculate terms in parentheses: +(-25x1/(5(15x+20)*6(12x-24))), so:

-25x1/(5(15x+20)*6(12x-24))

We multiply all the terms by the denominator


-25x1

We add all the numbers together, and all the variables

-25x

Back to the equation:

+(-25x)


We add all the numbers together, and all the variables

17x+(-25x)=0

We get rid of parentheses

17x-25x=0

We add all the numbers together, and all the variables

-8x=0

x=0/-8

x=0