4/5(10y-10)=2/7(7y=14)

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Solution for 4/5(10y-10)=2/7(7y=14) equation: 



4/5(10y-10)=2/7(7y=14)

We move all terms to the left:

4/5(10y-10)-(2/7(7y)=0



Domain of the equation: 5(10y-10)!=0

y∈R





Domain of the equation: 77y!=0

y!=0/77

y!=0

y∈R



We calculate fractions


308y/(3850y^2-3850y)+(-10y1/(3850y^2-3850y)=0



We calculate terms in parentheses: +(-10y1/(3850y^2-3850y), so:

-10y1/(3850y^2-3850y

We multiply all the terms by the denominator


-10y1

We add all the numbers together, and all the variables

-10y

Back to the equation:

+(-10y)



We get rid of parentheses

308y/(3850y^2-3850y)-10y=0

We multiply all the terms by the denominator


308y-10y*(3850y^2-3850y)=0

We multiply parentheses

-38500y^3+38500y^2+308y=0

We do not support eypression: y^3

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