4/5(10-20c)-(3c-10)-c=0.75(4c+12)-1/3(15-3c)-4

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Solution for 4/5(10-20c)-(3c-10)-c=0.75(4c+12)-1/3(15-3c)-4 equation: 



4/5(10-20c)-(3c-10)-c=0.75(4c+12)-1/3(15-3c)-4

We move all terms to the left:

4/5(10-20c)-(3c-10)-c-(0.75(4c+12)-1/3(15-3c)-4)=0



Domain of the equation: 5(10-20c)!=0

c∈R





Domain of the equation: 3(15-3c)-4)!=0

c∈R



We add all the numbers together, and all the variables

4/5(-20c+10)-(3c-10)-c-(0.75(4c+12)-1/3(-3c+15)-4)=0

We add all the numbers together, and all the variables

-1c+4/5(-20c+10)-(3c-10)-(0.75(4c+12)-1/3(-3c+15)-4)=0

We get rid of parentheses

-1c+4/5(-20c+10)-3c-(0.75(4c+12)-1/3(-3c+15)-4)+10=0

We calculate fractions


-1c-3c+(12c(-)/(5(-20c+10)*3(-3c+15))+(-(3c-5c0)/(5(-20c+10)*3(-3c+15))+10=0

We can not solve this equation

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