4/3y-2/y=5/3

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Solution for 4/3y-2/y=5/3 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

(4/3)*y-(2/y) = 5/3 // - 5/3

(4/3)*y-(2/y)-(5/3) = 0

(4/3)*y-2*y^-1-5/3 = 0

4/3*y^1-2*y^-1-5/3*y^0 = 0

(4/3*y^2-5/3*y^1-2*y^0)/(y^1) = 0 // * y^2

y^1*(4/3*y^2-5/3*y^1-2*y^0) = 0

y^1

(4/3)*y^2+(-5/3)*y-2 = 0

(4/3)*y^2+(-5/3)*y-2 = 0

DELTA = (-5/3)^2-(-2*4*(4/3))

DELTA = 121/9

DELTA > 0

y = ((121/9)^(1/2)-(-5/3))/(2*(4/3)) or y = (-(-5/3)-(121/9)^(1/2))/(2*(4/3))

y = 2 or y = -3/4

y in { -3/4, 2} 

y in { -3/4, 2 }

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