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4/3x=x+25
We move all terms to the left:
4/3x-(x+25)=0
Domain of the equation: 3x!=0We get rid of parentheses
x!=0/3
x!=0
x∈R
4/3x-x-25=0
We multiply all the terms by the denominator
-x*3x-25*3x+4=0
Wy multiply elements
-3x^2-75x+4=0
a = -3; b = -75; c = +4;
Δ = b2-4ac
Δ = -752-4·(-3)·4
Δ = 5673
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-75)-\sqrt{5673}}{2*-3}=\frac{75-\sqrt{5673}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-75)+\sqrt{5673}}{2*-3}=\frac{75+\sqrt{5673}}{-6} $
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