4/3x-4=x+1

Solution for 4/3x-4=x+1 equation:

4/3x-4=x+1

We move all terms to the left:

4/3x-4-(x+1)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We get rid of parentheses

4/3x-x-1-4=0

We multiply all the terms by the denominator


-x*3x-1*3x-4*3x+4=0

Wy multiply elements

-3x^2-3x-12x+4=0

We add all the numbers together, and all the variables

-3x^2-15x+4=0

a = -3; b = -15; c = +4;
Δ = b2-4ac
Δ = -152-4·(-3)·4
Δ = 273
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{273}}{2*-3}=\frac{15-\sqrt{273}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{273}}{2*-3}=\frac{15+\sqrt{273}}{-6}
$