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4/3x+x=28
We move all terms to the left:
4/3x+x-(28)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
x+4/3x-28=0
We multiply all the terms by the denominator
x*3x-28*3x+4=0
Wy multiply elements
3x^2-84x+4=0
a = 3; b = -84; c = +4;
Δ = b2-4ac
Δ = -842-4·3·4
Δ = 7008
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7008}=\sqrt{16*438}=\sqrt{16}*\sqrt{438}=4\sqrt{438}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-84)-4\sqrt{438}}{2*3}=\frac{84-4\sqrt{438}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-84)+4\sqrt{438}}{2*3}=\frac{84+4\sqrt{438}}{6} $
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