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4/3x+29=x
We move all terms to the left:
4/3x+29-(x)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
-1x+4/3x+29=0
We multiply all the terms by the denominator
-1x*3x+29*3x+4=0
Wy multiply elements
-3x^2+87x+4=0
a = -3; b = 87; c = +4;
Δ = b2-4ac
Δ = 872-4·(-3)·4
Δ = 7617
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(87)-\sqrt{7617}}{2*-3}=\frac{-87-\sqrt{7617}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(87)+\sqrt{7617}}{2*-3}=\frac{-87+\sqrt{7617}}{-6} $
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