4/3m+1/8m-6=15

Solution for 4/3m+1/8m-6=15 equation:

4/3m+1/8m-6=15

We move all terms to the left:

4/3m+1/8m-6-(15)=0


Domain of the equation: 3m!=0

m!=0/3

m!=0

m∈R



Domain of the equation: 8m!=0

m!=0/8

m!=0

m∈R


We add all the numbers together, and all the variables

4/3m+1/8m-21=0

We calculate fractions


32m/24m^2+3m/24m^2-21=0

We multiply all the terms by the denominator


32m+3m-21*24m^2=0

We add all the numbers together, and all the variables

35m-21*24m^2=0

Wy multiply elements

-504m^2+35m=0

a = -504; b = 35; c = 0;
Δ = b2-4ac
Δ = 352-4·(-504)·0
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-35}{2*-504}=\frac{-70}{-1008}
=5/72
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+35}{2*-504}=\frac{0}{-1008}
=0
$