4/3b=1/4b+3

Solution for 4/3b=1/4b+3 equation:

4/3b=1/4b+3

We move all terms to the left:

4/3b-(1/4b+3)=0


Domain of the equation: 3b!=0

b!=0/3

b!=0

b∈R



Domain of the equation: 4b+3)!=0

b∈R


We get rid of parentheses

4/3b-1/4b-3=0

We calculate fractions


16b/12b^2+(-3b)/12b^2-3=0

We multiply all the terms by the denominator


16b+(-3b)-3*12b^2=0

Wy multiply elements

-36b^2+16b+(-3b)=0

We get rid of parentheses

-36b^2+16b-3b=0

We add all the numbers together, and all the variables

-36b^2+13b=0

a = -36; b = 13; c = 0;
Δ = b2-4ac
Δ = 132-4·(-36)·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-13}{2*-36}=\frac{-26}{-72}
=13/36
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+13}{2*-36}=\frac{0}{-72}
=0
$