4/3(y+1)=3/2(y-2)

Solution for 4/3(y+1)=3/2(y-2) equation:

4/3(y+1)=3/2(y-2)

We move all terms to the left:

4/3(y+1)-(3/2(y-2))=0


Domain of the equation: 3(y+1)!=0

y∈R



Domain of the equation: 2(y-2))!=0

y∈R


We calculate fractions


(8yy/(3(y+1)*2(y-2)))+(-9yy/(3(y+1)*2(y-2)))=0


We calculate terms in parentheses: +(8yy/(3(y+1)*2(y-2))), so:

8yy/(3(y+1)*2(y-2))

We multiply all the terms by the denominator


8yy

Back to the equation:

+(8yy)



We calculate terms in parentheses: +(-9yy/(3(y+1)*2(y-2))), so:

-9yy/(3(y+1)*2(y-2))

We multiply all the terms by the denominator


-9yy

Back to the equation:

+(-9yy)


We get rid of parentheses

8yy-9yy=0