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4/3(x+3)=3/2(x+2)
We move all terms to the left:
4/3(x+3)-(3/2(x+2))=0
Domain of the equation: 3(x+3)!=0
x∈R
Domain of the equation: 2(x+2))!=0We calculate fractions
x∈R
(8xx/(3(x+3)*2(x+2)))+(-9xx/(3(x+3)*2(x+2)))=0
We calculate terms in parentheses: +(8xx/(3(x+3)*2(x+2))), so:
8xx/(3(x+3)*2(x+2))
We multiply all the terms by the denominator
8xx
Back to the equation:
+(8xx)
We calculate terms in parentheses: +(-9xx/(3(x+3)*2(x+2))), so:We get rid of parentheses
-9xx/(3(x+3)*2(x+2))
We multiply all the terms by the denominator
-9xx
Back to the equation:
+(-9xx)
8xx-9xx=0
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