4/3(15x-30)=4(2+x)

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Solution for 4/3(15x-30)=4(2+x) equation:



4/3(15x-30)=4(2+x)
We move all terms to the left:
4/3(15x-30)-(4(2+x))=0
Domain of the equation: 3(15x-30)!=0
x∈R
We add all the numbers together, and all the variables
4/3(15x-30)-(4(x+2))=0
We multiply all the terms by the denominator
-((4(x+2)))*3(15x-30)+4=0
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30
We calculate terms in parentheses: -((4(x+2)))*3(15x-30), so:
(4(x+2)))*3(15x-30

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