4/3(-9x+12)-x=16x-9

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Solution for 4/3(-9x+12)-x=16x-9 equation: 



4/3(-9x+12)-x=16x-9

We move all terms to the left:

4/3(-9x+12)-x-(16x-9)=0



Domain of the equation: 3(-9x+12)!=0

x∈R



We add all the numbers together, and all the variables

-1x+4/3(-9x+12)-(16x-9)=0

We get rid of parentheses

-1x+4/3(-9x+12)-16x+9=0

We multiply all the terms by the denominator


-1x*3(-9x+12)-16x*3(-9x+12)+9*3(-9x+12)+4=0

Wy multiply elements

-3x^2(--48x^2(-+27x(-+4=0

We use the square of the difference formula

-3x^2(+48x^2(-27x(-4=0

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