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4/2x=3/x-3
We move all terms to the left:
4/2x-(3/x-3)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: x-3)!=0We get rid of parentheses
x∈R
4/2x-3/x+3=0
We calculate fractions
4x/2x^2+(-6x)/2x^2+3=0
We multiply all the terms by the denominator
4x+(-6x)+3*2x^2=0
Wy multiply elements
6x^2+4x+(-6x)=0
We get rid of parentheses
6x^2+4x-6x=0
We add all the numbers together, and all the variables
6x^2-2x=0
a = 6; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·6·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*6}=\frac{0}{12} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*6}=\frac{4}{12} =1/3 $
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