4/17p+6=1/4p

Solution for 4/17p+6=1/4p equation:

4/17p+6=1/4p

We move all terms to the left:

4/17p+6-(1/4p)=0


Domain of the equation: 17p!=0

p!=0/17

p!=0

p∈R



Domain of the equation: 4p)!=0

p!=0/1

p!=0

p∈R


We add all the numbers together, and all the variables

4/17p-(+1/4p)+6=0

We get rid of parentheses

4/17p-1/4p+6=0

We calculate fractions


16p/68p^2+(-17p)/68p^2+6=0

We multiply all the terms by the denominator


16p+(-17p)+6*68p^2=0

Wy multiply elements

408p^2+16p+(-17p)=0

We get rid of parentheses

408p^2+16p-17p=0

We add all the numbers together, and all the variables

408p^2-1p=0

a = 408; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·408·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*408}=\frac{0}{816}
=0
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*408}=\frac{2}{816}
=1/408
$