4/(x+4)=8/(x+3)

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Solution for 4/(x+4)=8/(x+3) equation: 



4/(x+4)=8/(x+3)

We move all terms to the left:

4/(x+4)-(8/(x+3))=0



Domain of the equation: (x+4)!=0

We move all terms containing x to the left, all other terms to the right

x!=-4

x∈R





Domain of the equation: (x+3))!=0

x∈R



We calculate fractions


4x/((x+4)*(x+3)))+(-(8*(x+4))/((x+4)*(x+3)))=0



We calculate terms in parentheses: -(8*(x+4))/((x+4)*(x+3))), so:

8*(x+4))/((x+4)*(x+3))

We multiply all the terms by the denominator


8*(x+4))

We multiply parentheses

8x+

We add all the numbers together, and all the variables

8x

Back to the equation:

-(8x)



We add all the numbers together, and all the variables

-8x+4x/((x+4)*(x+3)))+(=0

We multiply all the terms by the denominator


-8x*((x+4)*(x+3)))+(+4x=0

We add all the numbers together, and all the variables

4x-8x*((x+4)*(x+3)))+(=0

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