4/(x+2)+6=14/(2x+4)

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Solution for 4/(x+2)+6=14/(2x+4) equation: 



4/(x+2)+6=14/(2x+4)

We move all terms to the left:

4/(x+2)+6-(14/(2x+4))=0



Domain of the equation: (x+2)!=0

We move all terms containing x to the left, all other terms to the right

x!=-2

x∈R





Domain of the equation: (2x+4))!=0

x∈R



We calculate fractions


8x/((x+2)*(2x+4)))+(-(14*(x+2))/((x+2)*(2x+4)))+6=0

We calculate fractions


(8x*((x+2)*(2x+4)))+6)/(((x+2)*(2x+4)))+(*((x+2)*(2x+4)))+6)+(-(14*(x+2))*((x+2)*(2x+4)))+()/(((x+2)*(2x+4)))+(*((x+2)*(2x+4)))+6)=0



We calculate terms in parentheses: +(8x*((x+2)*(2x+4))), so:

8x*((x+2)*(2x+4))



We can not solve this equation

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