4/(n+2)=7/nn+

Solution for 4/(n+2)=7/nn+ equation:

4/(n+2)=7/nn+

We move all terms to the left:

4/(n+2)-(7/nn+)=0


Domain of the equation: (n+2)!=0

We move all terms containing n to the left, all other terms to the right

n!=-2

n∈R



Domain of the equation: nn+)!=0

n∈R


We add all the numbers together, and all the variables

4/(n+2)-(+7/nn)=0

We get rid of parentheses

4/(n+2)-7/nn=0

We calculate fractions


4n/(n^2+2n)+(-7n-14)/(n^2+2n)=0

We multiply all the terms by the denominator


4n+(-7n-14)=0

We get rid of parentheses

4n-7n-14=0

We add all the numbers together, and all the variables

-3n-14=0

We move all terms containing n to the left, all other terms to the right

-3n=14

n=14/-3

n=-4+2/3