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4/(3x+2)-2/(3x)=1/(x+2)
We move all terms to the left:
4/(3x+2)-2/(3x)-(1/(x+2))=0
Domain of the equation: (3x+2)!=0
We move all terms containing x to the left, all other terms to the right
3x!=-2
x!=-2/3
x!=-2/3
x∈R
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: (x+2))!=0We calculate fractions
x∈R
(12x^2*()/((3x+2)*3x*(x+2)))+(-2*(3x+2)*(x+2)))/((3x+2)*3x*(x+2)))+(-(1*(3x+2)*3x)/((3x+2)*3x*(x+2)))=0
We calculate terms in parentheses: +(12x^2*()/((3x+2)*3x*(x+2))), so:
12x^2*()/((3x+2)*3x*(x+2))
We multiply all the terms by the denominator
12x^2*()
Back to the equation:
+(12x^2*())
We calculate terms in parentheses: +(-2*(3x+2)*(x+2)))/((3x+2)*3x*(x+2)))+(-(1*(3x+2)*3x)/((3x+2)*3x*(x+2))), so:
-2*(3x+2)*(x+2)))/((3x+2)*3x*(x+2)))+(-(1*(3x+2)*3x)/((3x+2)*3x*(x+2))
We add all the numbers together, and all the variables
-2*(3x+2)*(x+2)))/((3x+2)*3x*(x+2)))+(-(1*(3x+2)*3x)/((3x+2)*3x*(x
We multiply all the terms by the denominator
-2*(3x+2)*(x+2)))+2*3x*x*((3x+2))+(-(1*3x*((3x+2)*3x)+2*3x*x*((3x
Wy multiply elements
6x^3*x-2*(3x+2)*(x+2)))+2*3x*x*((3x+2))+(-(1*3x*((3x+2)*3x)
We do not support expression: x^3
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