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4.5x+8=29+1/5x
We move all terms to the left:
4.5x+8-(29+1/5x)=0
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
4.5x-(1/5x+29)+8=0
We get rid of parentheses
4.5x-1/5x-29+8=0
We multiply all the terms by the denominator
(4.5x)*5x-29*5x+8*5x-1=0
We add all the numbers together, and all the variables
(+4.5x)*5x-29*5x+8*5x-1=0
We multiply parentheses
20x^2-29*5x+8*5x-1=0
Wy multiply elements
20x^2-145x+40x-1=0
We add all the numbers together, and all the variables
20x^2-105x-1=0
a = 20; b = -105; c = -1;
Δ = b2-4ac
Δ = -1052-4·20·(-1)
Δ = 11105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-105)-\sqrt{11105}}{2*20}=\frac{105-\sqrt{11105}}{40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-105)+\sqrt{11105}}{2*20}=\frac{105+\sqrt{11105}}{40} $
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