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4.5+(3/5x)+10=2x+30
We move all terms to the left:
4.5+(3/5x)+10-(2x+30)=0
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+3/5x)-(2x+30)+4.5+10=0
We add all the numbers together, and all the variables
(+3/5x)-(2x+30)+14.5=0
We get rid of parentheses
3/5x-2x-30+14.5=0
We multiply all the terms by the denominator
-2x*5x-30*5x+(14.5)*5x+3=0
We multiply parentheses
-2x*5x-30*5x+72.5x+3=0
Wy multiply elements
-10x^2-150x+72.5x+3=0
We add all the numbers together, and all the variables
-10x^2-77.5x+3=0
a = -10; b = -77.5; c = +3;
Δ = b2-4ac
Δ = -77.52-4·(-10)·3
Δ = 6126.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-77.5)-\sqrt{6126.25}}{2*-10}=\frac{77.5-\sqrt{6126.25}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-77.5)+\sqrt{6126.25}}{2*-10}=\frac{77.5+\sqrt{6126.25}}{-20} $
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