4-x+2(3-x)=x+1+7(3-2x)

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Solution for 4-x+2(3-x)=x+1+7(3-2x) equation: 



4-x+2(3-x)=x+1+7(3-2x)

We move all terms to the left:

4-x+2(3-x)-(x+1+7(3-2x))=0

We add all the numbers together, and all the variables

-x+2(-1x+3)-(x+1+7(-2x+3))+4=0

We add all the numbers together, and all the variables

-1x+2(-1x+3)-(x+1+7(-2x+3))+4=0

We multiply parentheses

-1x-2x-(x+1+7(-2x+3))+6+4=0



We calculate terms in parentheses: -(x+1+7(-2x+3)), so:

x+1+7(-2x+3)

determiningTheFunctionDomain
x+7(-2x+3)+1

We multiply parentheses

x-14x+21+1

We add all the numbers together, and all the variables

-13x+22

Back to the equation:

-(-13x+22)



We add all the numbers together, and all the variables

-3x-(-13x+22)+10=0

We get rid of parentheses

-3x+13x-22+10=0

We add all the numbers together, and all the variables

10x-12=0

We move all terms containing x to the left, all other terms to the right

10x=12

x=12/10

x=1+1/5

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