4-5(2x+11)=-11+10(x+10)

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Solution for 4-5(2x+11)=-11+10(x+10) equation: 



4-5(2x+11)=-11+10(x+10)

We move all terms to the left:

4-5(2x+11)-(-11+10(x+10))=0

We multiply parentheses

-10x-(-11+10(x+10))-55+4=0



We calculate terms in parentheses: -(-11+10(x+10)), so:

-11+10(x+10)

determiningTheFunctionDomain
10(x+10)-11

We multiply parentheses

10x+100-11

We add all the numbers together, and all the variables

10x+89

Back to the equation:

-(10x+89)



We add all the numbers together, and all the variables

-10x-(10x+89)-51=0

We get rid of parentheses

-10x-10x-89-51=0

We add all the numbers together, and all the variables

-20x-140=0

We move all terms containing x to the left, all other terms to the right

-20x=140

x=140/-20

x=-7

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