4-4b+4b=-3-5(1-b)=

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Solution for 4-4b+4b=-3-5(1-b)= equation: 



4-4b+4b=-3-5(1-b)=

We move all terms to the left:

4-4b+4b-(-3-5(1-b))=0

We add all the numbers together, and all the variables

-4b+4b-(-3-5(-1b+1))+4=0

We add all the numbers together, and all the variables

-(-3-5(-1b+1))+4=0



We calculate terms in parentheses: -(-3-5(-1b+1)), so:

-3-5(-1b+1)

determiningTheFunctionDomain
-5(-1b+1)-3

We multiply parentheses

5b-5-3

We add all the numbers together, and all the variables

5b-8

Back to the equation:

-(5b-8)



We get rid of parentheses

-5b+8+4=0

We add all the numbers together, and all the variables

-5b+12=0

We move all terms containing b to the left, all other terms to the right

-5b=-12

b=-12/-5

b=2+2/5

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