4-3(j-2)=3(-j-1)

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Solution for 4-3(j-2)=3(-j-1) equation: 



4-3(j-2)=3(-j-1)

We move all terms to the left:

4-3(j-2)-(3(-j-1))=0

We add all the numbers together, and all the variables

-3(j-2)-(3(-1j-1))+4=0

We multiply parentheses

-3j-(3(-1j-1))+6+4=0



We calculate terms in parentheses: -(3(-1j-1)), so:

3(-1j-1)

We multiply parentheses

-3j-3

Back to the equation:

-(-3j-3)



We add all the numbers together, and all the variables

-3j-(-3j-3)+10=0

We get rid of parentheses

-3j+3j+3+10=0

We add all the numbers together, and all the variables

13!=0

There is no solution for this equation

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