4-3(5b-7)=-4(4b-5)+6b

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Solution for 4-3(5b-7)=-4(4b-5)+6b equation:



4-3(5b-7)=-4(4b-5)+6b
We move all terms to the left:
4-3(5b-7)-(-4(4b-5)+6b)=0
We multiply parentheses
-15b-(-4(4b-5)+6b)+21+4=0
We calculate terms in parentheses: -(-4(4b-5)+6b), so:
-4(4b-5)+6b
We add all the numbers together, and all the variables
6b-4(4b-5)
We multiply parentheses
6b-16b+20
We add all the numbers together, and all the variables
-10b+20
Back to the equation:
-(-10b+20)
We add all the numbers together, and all the variables
-15b-(-10b+20)+25=0
We get rid of parentheses
-15b+10b-20+25=0
We add all the numbers together, and all the variables
-5b+5=0
We move all terms containing b to the left, all other terms to the right
-5b=-5
b=-5/-5
b=1

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