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4-2c=-2(c+1)
We move all terms to the left:
4-2c-(-2(c+1))=0
We calculate terms in parentheses: -(-2(c+1)), so:We get rid of parentheses
-2(c+1)
We multiply parentheses
-2c-2
Back to the equation:
-(-2c-2)
-2c+2c+2+4=0
We add all the numbers together, and all the variables
6!=0
There is no solution for this equation
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