4-2(1+k)=3(k-2)-6k

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Solution for 4-2(1+k)=3(k-2)-6k equation: 



4-2(1+k)=3(k-2)-6k

We move all terms to the left:

4-2(1+k)-(3(k-2)-6k)=0

We add all the numbers together, and all the variables

-2(k+1)-(3(k-2)-6k)+4=0

We multiply parentheses

-2k-(3(k-2)-6k)-2+4=0



We calculate terms in parentheses: -(3(k-2)-6k), so:

3(k-2)-6k

We add all the numbers together, and all the variables

-6k+3(k-2)

We multiply parentheses

-6k+3k-6

We add all the numbers together, and all the variables

-3k-6

Back to the equation:

-(-3k-6)



We add all the numbers together, and all the variables

-2k-(-3k-6)+2=0

We get rid of parentheses

-2k+3k+6+2=0

We add all the numbers together, and all the variables

k+8=0

We move all terms containing k to the left, all other terms to the right

k=-8

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