4-12y=2(-6+3y)

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Solution for 4-12y=2(-6+3y) equation: 



4-12y=2(-6+3y)

We move all terms to the left:

4-12y-(2(-6+3y))=0

We add all the numbers together, and all the variables

-12y-(2(3y-6))+4=0



We calculate terms in parentheses: -(2(3y-6)), so:

2(3y-6)

We multiply parentheses

6y-12

Back to the equation:

-(6y-12)



We get rid of parentheses

-12y-6y+12+4=0

We add all the numbers together, and all the variables

-18y+16=0

We move all terms containing y to the left, all other terms to the right

-18y=-16

y=-16/-18

y=8/9

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