4-(r+2)=4(2-4r)

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Solution for 4-(r+2)=4(2-4r) equation: 



4-(r+2)=4(2-4r)

We move all terms to the left:

4-(r+2)-(4(2-4r))=0

We add all the numbers together, and all the variables

-(r+2)-(4(-4r+2))+4=0

We get rid of parentheses

-r-(4(-4r+2))-2+4=0



We calculate terms in parentheses: -(4(-4r+2)), so:

4(-4r+2)

We multiply parentheses

-16r+8

Back to the equation:

-(-16r+8)



We add all the numbers together, and all the variables

-1r-(-16r+8)+2=0

We get rid of parentheses

-1r+16r-8+2=0

We add all the numbers together, and all the variables

15r-6=0

We move all terms containing r to the left, all other terms to the right

15r=6

r=6/15

r=2/5

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