4-(q-2)=-3-4(q+6)

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Solution for 4-(q-2)=-3-4(q+6) equation: 



4-(q-2)=-3-4(q+6)

We move all terms to the left:

4-(q-2)-(-3-4(q+6))=0

We get rid of parentheses

-q-(-3-4(q+6))+2+4=0



We calculate terms in parentheses: -(-3-4(q+6)), so:

-3-4(q+6)

determiningTheFunctionDomain
-4(q+6)-3

We multiply parentheses

-4q-24-3

We add all the numbers together, and all the variables

-4q-27

Back to the equation:

-(-4q-27)



We add all the numbers together, and all the variables

-1q-(-4q-27)+6=0

We get rid of parentheses

-1q+4q+27+6=0

We add all the numbers together, and all the variables

3q+33=0

We move all terms containing q to the left, all other terms to the right

3q=-33

q=-33/3

q=-11

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