4-(n+2)=3(n-4)

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Solution for 4-(n+2)=3(n-4) equation:


Simplifying
4 + -1(n + 2) = 3(n + -4)

Reorder the terms:
4 + -1(2 + n) = 3(n + -4)
4 + (2 * -1 + n * -1) = 3(n + -4)
4 + (-2 + -1n) = 3(n + -4)

Combine like terms: 4 + -2 = 2
2 + -1n = 3(n + -4)

Reorder the terms:
2 + -1n = 3(-4 + n)
2 + -1n = (-4 * 3 + n * 3)
2 + -1n = (-12 + 3n)

Solving
2 + -1n = -12 + 3n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-3n' to each side of the equation.
2 + -1n + -3n = -12 + 3n + -3n

Combine like terms: -1n + -3n = -4n
2 + -4n = -12 + 3n + -3n

Combine like terms: 3n + -3n = 0
2 + -4n = -12 + 0
2 + -4n = -12

Add '-2' to each side of the equation.
2 + -2 + -4n = -12 + -2

Combine like terms: 2 + -2 = 0
0 + -4n = -12 + -2
-4n = -12 + -2

Combine like terms: -12 + -2 = -14
-4n = -14

Divide each side by '-4'.
n = 3.5

Simplifying
n = 3.5

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