4-(h+2)=1-(5-7h)

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Solution for 4-(h+2)=1-(5-7h) equation: 



4-(h+2)=1-(5-7h)

We move all terms to the left:

4-(h+2)-(1-(5-7h))=0

We add all the numbers together, and all the variables

-(h+2)-(1-(-7h+5))+4=0

We get rid of parentheses

-h-(1-(-7h+5))-2+4=0



We calculate terms in parentheses: -(1-(-7h+5)), so:

1-(-7h+5)

determiningTheFunctionDomain
-(-7h+5)+1

We get rid of parentheses

7h-5+1

We add all the numbers together, and all the variables

7h-4

Back to the equation:

-(7h-4)



We add all the numbers together, and all the variables

-1h-(7h-4)+2=0

We get rid of parentheses

-1h-7h+4+2=0

We add all the numbers together, and all the variables

-8h+6=0

We move all terms containing h to the left, all other terms to the right

-8h=-6

h=-6/-8

h=3/4

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