4-(c+6)=3(c-5)+1

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Solution for 4-(c+6)=3(c-5)+1 equation: 


Simplifying
4 + -1(c + 6) = 3(c + -5) + 1

Reorder the terms:
4 + -1(6 + c) = 3(c + -5) + 1
4 + (6 * -1 + c * -1) = 3(c + -5) + 1
4 + (-6 + -1c) = 3(c + -5) + 1

Combine like terms: 4 + -6 = -2
-2 + -1c = 3(c + -5) + 1

Reorder the terms:
-2 + -1c = 3(-5 + c) + 1
-2 + -1c = (-5 * 3 + c * 3) + 1
-2 + -1c = (-15 + 3c) + 1

Reorder the terms:
-2 + -1c = -15 + 1 + 3c

Combine like terms: -15 + 1 = -14
-2 + -1c = -14 + 3c

Solving
-2 + -1c = -14 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
-2 + -1c + -3c = -14 + 3c + -3c

Combine like terms: -1c + -3c = -4c
-2 + -4c = -14 + 3c + -3c

Combine like terms: 3c + -3c = 0
-2 + -4c = -14 + 0
-2 + -4c = -14

Add '2' to each side of the equation.
-2 + 2 + -4c = -14 + 2

Combine like terms: -2 + 2 = 0
0 + -4c = -14 + 2
-4c = -14 + 2

Combine like terms: -14 + 2 = -12
-4c = -12

Divide each side by '-4'.
c = 3

Simplifying
c = 3

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