4-(5x-3)+(6x+3)/3=38

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Solution for 4-(5x-3)+(6x+3)/3=38 equation: 



4-(5x-3)+(6x+3)/3=38

We move all terms to the left:

4-(5x-3)+(6x+3)/3-(38)=0

We add all the numbers together, and all the variables

-(5x-3)+(6x+3)/3-34=0

We get rid of parentheses

-5x+(6x+3)/3+3-34=0

We multiply all the terms by the denominator


-5x*3+(6x+3)+3*3-34*3=0

We add all the numbers together, and all the variables

-5x*3+(6x+3)-93=0

Wy multiply elements

-15x+(6x+3)-93=0

We get rid of parentheses

-15x+6x+3-93=0

We add all the numbers together, and all the variables

-9x-90=0

We move all terms containing x to the left, all other terms to the right

-9x=90

x=90/-9

x=-10

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