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4-(3-x)=8-5(2x-3)
We move all terms to the left:
4-(3-x)-(8-5(2x-3))=0
We add all the numbers together, and all the variables
-(-1x+3)-(8-5(2x-3))+4=0
We get rid of parentheses
1x-(8-5(2x-3))-3+4=0
We calculate terms in parentheses: -(8-5(2x-3)), so:We add all the numbers together, and all the variables
8-5(2x-3)
determiningTheFunctionDomain -5(2x-3)+8
We multiply parentheses
-10x+15+8
We add all the numbers together, and all the variables
-10x+23
Back to the equation:
-(-10x+23)
x-(-10x+23)+1=0
We get rid of parentheses
x+10x-23+1=0
We add all the numbers together, and all the variables
11x-22=0
We move all terms containing x to the left, all other terms to the right
11x=22
x=22/11
x=2
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